Re: 450nm-es fényforrás?

[HWSW Famulus]

>> BLUE 450 and 473nm InGaN
>
> Csak úgy brahiból megnéztem a RET katalógusban (éppen ez van) a
> nagyfényereju kék ledeket, hogy mibe is kerülnek cirka.
> Hát, egy 1300mc, 470nm (ez már sok) példány 348.-Ft br.
> Épp azon tökölök, vajjon ebbol hány kellene a 10.000 lux fényerohöz?!
> Vagy, hááát erre holnap még1x rákérdezek, mert télleg baromi soknak
> tunik.
>
>
> üdv: I.

...akkor tajkepnek.

http://www.electro-optical.com/whitepapers/candela.htm

Photometric Units Candela
Systeme International (CI) unit of luminous intensity. The modern 
calibration reference is a platinum radiator heated to just below its 
melting point: each square cm of such an object has 60.0 candela luminous 
intensity! (In old-fashioned parlance, each sq. cm of the hot platinum emits 
as much light as 60 standard candles.) A point source of 1 candela radiates 
1 lumen into a solid angle of 1 steradian. A 1 sq-cm source of 1 candela 
produces an illumination level of 1 foot candle at a distance of 1 foot. It 
gets a little confusing at times, because there are 3 ways of measuring the 
light output of sources:

1) Total luminous flux,

2) Luminous intensity or surface brightness per unit area (Summing this up 
over a surface gives total flux, but a point source has no area so you can't 
really calculate its intensity.) See below.

3) Illumination level at some distance away, sometimes measured in 
foot-candles. Luminous intensity is surface brightness, sometimes measured 
in candelas. Note that a big surface can have a high luminance at the same 
time that it has a low luminous intensity and vice-versa. An example will 
make this clear (I hope):

A 40W fluorescent tube is a lot easier to stare at than a 40W incandescent. 
Why? The light output of the incandescent is spread over a much smaller 
area, so it has a much higher luminous intensity. The 40W fluor. puts out 
about 2000 lumens spread out over about 2500sq-cm. Meanwhile, the incand. 
puts out only about 750lumens, but it's spread over only about 150sq-cm 
(assuming a frosted bulb). So, the surface of the incandescent will have 
about 6 times greater luminous intensity. Imagine how bright the filament 
itself is, with its much smaller surface area. So, as you look at a CRT or 
other display, its surface brightness can be measured in candelas. It it has 
60candela brightness, it's as bright as the Pt standard. Another way to look 
at it is that each sq-cm would emit the same luminous flux as 60 candles! 
However, the intensity of a candle flame is another matter: it depends on 
the size of the flame! Here's an example of a practical problem:

Q. What's the luminous intensity of a white screen illuminated by 9 ft-cd 
lighting? (This is like slightly dimmed office lighting..I chose the value 9 
to make calculation easier, see below.) [Here's the significance of this 
question: In order to see images projected onto the white screen under such 
conditions, the display projector must produce at least a comparable level 
of luminosity.]

A. There are about 900 sq-cm per sq ft. For 9 ft-cd illumination, it's as if 
each sq ft of the screen were illuminated by a 9 candle source at a range of 
1 ft. Those 9 candles of flux are spread over 900 sq-cm of area, so each 
sq-cm has an intensity of 10 millicandelas! In order to be seen clearly, the 
display device should provide a luminous intensity significantly higher than 
10 mcd.

0) Standard candle - a point source of light having a particular radiance 
spectrum (power vs wavelength) and total power output which are approx. that 
of an 'ordinary' candle. Point sources radiate uniformly into a sphere.

1)1 Lumen - the amount of visible light emitted by a standard candle through 
a solid angle of 1 steradian. Since a sphere has 4pi = 12.57 steradians, the 
standard candle emits a total of 12.57 lumens. (Of course, 1 Steradian is 
just that solid angle over which the subtended area is exactly equal to the 
radius of a sphere, so, 1 sq-ft of surface area on a 1 ft sphere covers 
exactly 1 steradian.) Foot candle = 1 lumen/sq-ft, which is the illumination 
from 1 standard candle at 1 foot range.

2) 1 Lux = 1 meter-candle, i.e., illumination from 1 std cdl at 1 meter 
range. Since there are 10.76 sq ft per sq meter, it follows that there are 
10.76 lux per foot candle.

3) Illuminance of noonday sun - ~ 10,000 ft-cd, which is 107,600 lux. Since 
the sun is about 1,116,000,000 ft away, it's visible energy output must be 
about 1.245456e+18 candles!

4) Illumination levels in various other settings: Office illumination: 50 to 
200 ft-cd Art galleries 10 to 50 ft-cd Hospital operating table 1000 ft-cd 
Moonlight, full moon 0.01 ft-cd Major league baseball 100 ft-cd

5) Lumen outputs of various sources: Incandescent lamps, inside frosted 20 
lumens/Watt Fluorescent lamps, cool white 50 lumens/Watt

6) Calculating illumination level: In general, if the light from an x lumen 
source is spread over y square feet, the average illumination level will be 
x/y ft-cd.


KJ